纸牌游戏：十点半

纸牌游戏：十点半 设计 题目:纸牌游戏:十点半 学院:化学工程学院 专业:制药工程 班级:050607班 姓名:李艳明 指导教师: 设计日期: 2007年1月10日 一(选题背景 扑克牌是一种大众化的游戏牌，日常生活中我们为了娱乐消遣经常用之来进行一 些小游戏，如红心大战，斗地主，活龙等，多种多样。 十点半是这些游戏中一种比较简单的玩法。这个程序模仿了十点半的各个过程， 将游戏在程序运行中表示其玩法过程。 二.设计思想 (一)游戏规则:游戏可为两人或多人，但不超过八人。本游戏中选了人与电脑及 四人间的玩法为例。第一轮玩家依次取一张牌，之后玩家根据自己牌的总点数，选择 继续要牌或不要牌，但一旦选择不要牌以后就不能再要牌。玩家牌的总点数一旦超过 10.5，不能再要牌，J，Q，K算为半点。如果玩家牌的总点数都大于或小于10.5，点大者 胜;如果有大于也有小于10.5，则点数最小者赢。 (二)任何一张纸牌都有其本身的属性:花色，数值及起其所代表的点数。为将这些 特征表示出来，特定义一个结构体数组来表示一副扑克牌，由于十点半游戏中不需要 大小王，故可以定义如下: Struct book{ int color; char number; float num; }Card[52]; (三)不论何种扑克游戏都有其必经的三个步骤:一是有一副牌(即牌的初始化) 二是洗牌，三是发牌。这三个步骤在程序中通过三个函数来实现: void Build_Show(int HuaSe[],float DianShu[],char ShuZi[]); void Wash_Card(void); void Get_Card(int n); 三(流程图 for 调用函数 do循环 调用函数 终止 Main()函数流程图 Build_Show()的流程图 Wash_Card()的流程图 for for i=0 i=0 i<4 结束 i<1000 puts() for 产生rand1,rand2 i++ for j=0 i++ i=0,j=0 j<13 Rand1!=rand2 j++ j<52 交换牌 Card[j+13*i].color=HuaSe[i] Card[j+13*i].number=ShuZi[i] j%13==0 Card[j+13*i].num=DianShu[i] \n printf() 结束 Get_Card()的流程图 DuoRen()的流程图 调用函数 调用函数 if 每个人都拿第一张牌 n==1 n==4 当所有人都不能 拿牌时结束循环 人与电脑游 戏并输出游 戏结果 调用函数 Duo_Ren() 公布结果，由各 人的点数可知 调用结束 调用结束 四。程序清单 #define N 5 #include #include struct book{ int color; char number; float num; } Card[52]; /*To store the color,number and the points*/ void Build_Show(int HuaSe[], float DianShu[], char ShuZi[]); /*Establish a pair of cards and show it to the player*/ void Wash_Card(void); /*Wash the cards*/ void Get_Card(int n) ; /*Give the player cards and the result*/ void DuoRen(); int main(void) { int flag, n; the color*/ int HuaSe[4]={3,4,5,6}; /*Store char ShuZi[13]={'A','K','Q','J','0','9','8','7','6','5','4','3','2'}; /*Store the number*/ float DianShu[13]={1,0.5,0.5,0.5,10,9,8,7,6,5,4,3,2};/*Store the points*/ Build_Show(HuaSe, DianShu,ShuZi); /*Establish the card and show it*/ do{ Wash_Card(); /*Wash cards*/ a: puts("\nPlease input the number of the player:"); scanf("%d", &n); switch(n) { case 1:puts("You play with the computer!"); break; case 2:puts(:You two play!:); break; case 3:puts("You three play!"); break; case 4:puts("You four play!"); break; case 5:puts("You five play!"); break; case 6:puts("You six play!"); break; case 7:puts("You seven play!"); break; case 8:puts("You eight play!"); break; default:puts("The number of the players is too large!"); goto a; } Get_Card(n); /*Hand out the cards and give the result*/ do{ puts("\nDo you want to play again?1 represents yes and 0 no:"); scanf("%d", &flag); }while(flag != 1 && flag != 0); } while(flag == 1); } void Build_Show(int HuaSe[], float DianShu[], char ShuZi[]) { int i, j; for(i=0; i<4; i++) /*Establish a pair of cards*/ for(j=0; j<13; j++) { +13*i].color = HuaSe[i]; Card[j Card[j+13*i].number = ShuZi[j]; Card[j+13*i].num = DianShu[j]; } puts("This is a new pair of cards:"); /*Show the whole pair to the players to check*/ for(i=0,j=0; i<52; i++,j++) { if(!(j%13)) printf("\n"); printf ("%c%c", Card[i].color , Card[i].number); } } void Wash_Card(void) { int i,rand1,rand2,hua; char dian; float shu; for(i=0; i<1; i++) { rand1=random(52); /*Get a card by random,and put the cards into mess*/ rand2=random(52); if(rand1!=rand2) hua=Card[rand1].color; Card[rand1].color=Card[rand2].color; Card[rand2].color=hua; dian=Card[rand1].number; Card[rand1].number=Card[rand2].number; Card[rand2].number=dian; shu=Card[rand1].num; Card[rand1].num=Card[rand2].num; Card[rand2].num=shu; } } void Get_Card(int n) /*Hand out the cards one by one and give the result*/ { int i=0, j=0, k=0, flag=1, flag2=1; float sum_m=0, sum_c=0; struct book Man[52], Computer[52]; if(n == 1) { while(flag == 1 && i < 52) { Man[j++]=Card[i++]; /*Man gets the card firstly*/ sum_m += Man[j-1].num; /*Acumulate the whole points of the man*/ if(flag2 == 1 && i < 52 && (sum_m <= 10.5 &&sum_c <= 10.5 && (sum_c + Card[i].num) <= 10.5|| sum_m > 10.5 && (sum_c + Card[i].num) >=sum_m)) /*Let the computer know what the next card is and decide whetherto get a card */ { Computer[k++]=Card[i++]; /*The computer gets a card*/ sum_c += Computer[k-1].num; /*Acumulate the whole points of the computer*/ } else flag2=0; printf("\n"); puts("Now the cards you get are:"); for(i=0; i 10.5 && (sum_c + Card[i].num) >=sum_m)) /*Let the computer knonws what the next card is and decide wheter to get one*/ { Computer[k++]=Card[i++]; sum_c += Computer[k-1].num; > 10.5) if( sum_c break; } puts("Okay,now give out the result:"); puts("Now the cards you've got are:"); for( i=0; i 10.5 && sum_c > 10.5)||(sum_m <= 10.5&& sum_c <= 10.5)) if(sum_m > sum_c) !It's unbelievable!"); puts("You win the computer else if(sum_m == sum_c) puts("You play as well as the computer,and you're really good."); else puts("The computer wins and you need more practice!"); else if(sum_m <= 10.5 && sum_c > 10.5) puts("You win the computer!It's unbelievable!"); else puts("The computer wins and you need more practice!"); } else DuoRen(); } void DuoRen() { struct book Man[N][52]; int i, a[N]={0}, k=0, flag[N], flag2=1, s=0,m=0; float sum[N]={0},q,t; for(i=0; i 10.5) flag[i]=0; } s=0; for(k=0; k