Bash字符串处理（与Java对照） - 20_查找子串的位置

Bash字符串处理（与Java对照） - 20_查找子串的位置 Bash字符串处理(与Java对照) - 20.查找子串的位置 In Java String.indexOf int indexOf(String str) 返回第一次出现的指定子字符串在此字符串中的索引。 int indexOf(String str, int fromIndex) 从指定的索引处开始，返回第一次出现的指定子字符串在此字符串 中的索引。 int lastIndexOf(String str) 返回在此字符串中最右边出现的指定子字符串的索引。 int lastIndexOf(String str, int fromIndex) 从指定的索引处开始向后搜索，返回在此字符串中最后一次出现的 指定子字符串的索引。 StringUtils.indexOf & StringUtils.lastIndexOf static int indexOf(String str, String searchStr) Finds the first index within a String, handling null. static int indexOf(String str, String searchStr, int startPos) Finds the first index within a String, handling null. static int indexOfAny(String str, String[] searchStrs) Find the first index of any of a set of potential substrings. static int indexOfIgnoreCase(String str, String searchStr) Case in-sensitive find of the first index within a String. static int indexOfIgnoreCase(String str, String searchStr, int startPos) Case in-sensitive find of the first index within a String from the specified position. static int lastIndexOf(String str, String searchStr) Finds the last index within a String, handling null. static int lastIndexOf(String str, String searchStr, int startPos) Finds the first index within a String, handling null. static int lastIndexOfAny(String str, String[] searchStrs) Find the latest index of any of a set of potential substrings. static int lastIndexOfIgnoreCase(String str, String searchStr) Case in-sensitive find of the last index within a String. static int lastIndexOfIgnoreCase(String str, String searchStr, int startPos) Case in-sensitive find of the last index within a String from the specified position. static int lastOrdinalIndexOf(String str, String searchStr, int ordinal) Finds the n-th last index within a String, handling null. static int ordinalIndexOf(String str, String searchStr, int ordinal) Finds the n-th index within a String, handling null. In Bash 使用遍历字符串的来查找子串的位置 函数:strstr _{如果找到，打印位置，从0开始计数，退出码为0;否则，打印-1，退出码为1 strstr(){ declare -i i n2=${#2} n1=${#1}-n2 #echo $i $n1 $n2 for ((i=0; i}