计算下个有相同星期的闰年是那一年输入1896的时候显示的不对呢解决办法

计算下个有相同星期的闰年是那一年输入1896的时候显示的不对呢解决办法 计算下个有相同星期的闰年是那一年，为什么输入1896的时候显示的不对呢, [code=Java][/code] import java.util.Scanner; public class LeapYear{ public static void main(String[] args){ System.out.println( Please enter a year greater than 1582. ); Scanner scan=new Scanner(System.in); int year=scan.nextInt(); int month=2,day=29; if(year =1582){ if(isLeapYear(year)){ System.out.println( \n +year+ is leap year ); Zellers(year,month,day); } else{ System.out.println( \n +year+ is not leap year ); } } else{ System.out.println( \nThe year that entered is out of range. ); } } public static boolean isLeapYear(int year){ if (year%4==0 year%100!=0){ return true; } else{ if (year%400==0) return true; } return false; } public static void Zellers(int year,int month,int day){ int LeapFactor,DayNumber,StartMonth,StartYear; if (month 3) { StartMonth=0; StartYear=year-1; } else { StartMonth = (int) (0.4*month+2.3); StartYear = year; } LeapFactor =(StartYear/4)-(StartYear/100)+(StartYear/400); DayNumber=((365*year+31*(month-1)+day+LeapFactor-StartMonth)-1)%7; System.out.println( \n +DisplayDay(DayNumber)+ was Feb 29th in +year); for (int year1=year; year1 1582; year1++) { int DayNumber1=((365*year1+31*(month-1)+day+LeapFactor-StartMonth)-1)%7; if(isLeapYear(year1) DayNumber1==DayNumber) { System.out.println( \n +year1+ is the next leap year where Feb. 29th happens on +DisplayDay(DayNumber)); System.out.println( \n**********************************END************************************ ); return; } } } public static String DisplayDay(int DayNumber){ switch (DayNumber) { case 0: return Sunday ; case 1: return Monday ; case 2: return Tuesday ; case 3: return Wednesday ; case 4: return Thursday ; case 5: return Friday ; case 6: return Saturday ; default: return ; } } } ------解决-------------------------------------------------------- 1986年貌似不是闰年吧 ------解决方案-------------------------------------------------------- 看错，是1896。 试了哈，是正确的，没有问啊