Wewillcontinuetoimprovethepany'sinternalcontrolsystem,andsteadyimprovementinabilitytomanageandcontrol,optimizebusinessprocesses,toensuresmoothprocesses,responsibilitiesinplace;tofurtherstrengtheninternalcontrols,playacontrolpostindependentoversightroleofevaluationplyingwiththird-partyresponsibility;toactivelymakeuseofinternalaudittoolsdetectpotentialmanagement,streamline,standardizerelatedtransactions,strengtheningoperationsinaccordancewithlaw.Deepeningtheinformationmanagementtoensurefullmunication"zeroresistance". ToconstantlyperfectERP,andBFS++,andPI,andMIS,andSCM,informationsystembasedconstruction,fullintegrationinformationsystem,achievedinformationresourcesshared;toexpandPortalsystemapplicationofbreadthanddepth,playinformationsystemonenterpriseofAssistantrole;toperfectdailyrunmaintenanceoperationofrecords,promoteproblemreasonsanalysisandsystemhandover;tostrengtheningBFS++,andERP,andSCM,technologyapplicationoftraining,improveemployeesapplicationinformationsystemofcapacityandlevel.Humanisticcaretoensure"zero." TostrengtheningHumanitiescare,continuestofosterpanywindclear,andgasare,andheartShunofcultureatmosphere;strengtheninglovehelpedtrapped,caredifficultemployees;carriedoutstyleactivities,richemployeeslife;strengtheninghealthandlabourprotection,organizationcareerhealthmedical,controlcareeragainst;continuestoimplementationpsychologicalwarningpreventionsystem,trainingemployeeshealthofcharacter,andstableofmoodandenterprisingofattitude,createdfriendlyfraternityofHumanitiesenvironment.Tostrengthenriskmanagement,ensurethatthebusinessof"zerorisk".Tostrengthenedbusinessplansmanagement,willbusinessbusinessplanscovertoalllevel,ensurethebusinesscancontrolincontrol;tocloseconcernfinancial,andcoalelectriclinkage,andenergy-savingscheduling,nationalpolicytrends,strengtheningtrack,activeshould;toimplementationState-ownedassetsmethod,furtherspecificationbusinessfinancialmanagement;toperfectrisktubecontrolsystem,achievedriskrecognition,andmeasure,andassessment,andreport,andcontrolfeedbackofclosedringmanagement,improveriskpreventioncapacity. Tofurtherstandardizetrading,andstrivetoachieve"accordingtolaw,standardizeandfair."Innovationofperformancemanagement,toensurethatpotentialemployees"zerofly".Tostrengthenperformancemanagement,processcontrol,enhanceemployeeevaluationandlevelsofeffectivemunicationtoimproveperformancemanagement.Tofurtherquantifyandrefineemployeestandards...Work,fullplayparty,andbranch,andmembersin"fivetypeEnterprise"constructionintheofcorerole,andfightingfortressroleandpioneermodelrole;tocontinuestostrengthening"fourgood"leadershipconstruction,fullplaylevelscadresinenterprisedevelopmentinthe-.门急诊医技楼外脚手架采用悬挑式单排脚手架,根底回填后改为落地式双排脚手架,脚手架搭设高度为23m。病房医技楼外脚手架采用悬挑双排脚手架,分四次悬挑ofbackbonebackbonerole;tofullstrengtheningmembersyouthwork,fullplayyouthemployeesinpanydevelopmentintheofforcerole;toimproveindependentmissionagainstcorruptionworklevel,strengtheningonenterprisebusinesskeylinkofeffectivenessmonitored.,Andmaintainstability.Tofurtherstrengthenpublicityandeducation,improvetheoveralllegalsystem.Wemuststrengthensafetymanagement,establishandimprovetheeducation,supervision,andevaluationasoneofthetrafficsafetymanagementmechanism. ToconscientiouslysumuptheOlympicsecuritycontrols,promotingintegratedmanagementtoahigherlevel,higherstandards,ahigherlevelofdevelopment.Employees,todayislunarcalendaronDecember24,theoxBellisabouttoring,atthistimeofyear,weclearlyfeelthepulseoftheXXpowergenerationpanytoflourish,tomoreclearlyhearXXpowergenerationpaniesmatureandsymmetrybreathing.Recallingpastoneanotheracrossarailing,weareenthusiasticandfullofconfidence.Futuredevelopmentopportunities,wemoreexcitingfightmorespirited. Employees,letustogetheracross2021fullofchallengesandopportunities,tocreateagreen,low-costoperation,fullofhumanecareofaworld-classpowergenerationpanyandworkhard!TheoccasionoftheSpringFestival,mysincerewishthatyouandthefamiliesofthestaffinthenewyear,goodhealth,happy,happy-.word.zl.......资料...严蔚敏数据构造C语言版
详解第1章绪论1.1简述以下术语:数据,数据元素、数据对象、数据构造、存储构造、数据类型和抽象数据类型。解:数据是对客观事物的符号
示。在计算机科学中是指所有能输入到计算机中并被计算机程序处理的符号的总称。数据元素是数据的根本单位,在计算机程序常作为一个整体进展考虑和处理。数据对象是性质一样的数据元素的集合,是数据的一个子集。数据构造是相互之间存在一种或多种特定关系的数据元素的集合。存储构造是数据构造在计算机中的表示。数据类型是一个值的集合和定义在这个值集上的一组操作的总称。抽象数据类型是指一个
模型以及定义在该模型上的一组操作。是对一般数据类型的扩展。1.2试描述数据构造和抽象数据类型的概念与程序设计语言中数据类型概念的区别。解:抽象数据类型包含一般数据类型的概念,但含义比一般数据类型更广、更抽象。一般数据类型由具体语言系统部定义,直接提供应编程者定义用户数据,因此称它们为预定义数据类型。抽象数据类型通常由编程者定义,包括定义它所使用的数据和在这些数据上所进展的操作。在定义抽象数据类型中的数据局部和操作局部时,要求只定义到数据的逻辑构造和操作说明,不考虑数据的存储构造和操作的具体实现,这样抽象层次更高,更能为其他用户提供良好的使用接口。1.3设有数据构造(D,R),其中,,试按图论中图的画法惯例画出其逻辑构造图。解:1.4试仿照三元组的抽象数据类型分别写出抽象数据类型复数和有理数的定义〔有理数是其分子、分母均为自然数且分母不为零的分数〕。解:ADTplex{数据对象:D={r,i|r,i为实数}数据关系:R={
}根本操作:Initplex(&C,re,im)操作结果:构造一个复数C,其实部和虚局部别为re和imDestroyCmoplex(&C)操作结果:销毁复数CGet(C,k,&e)操作结果:用e返回复数C的第k元的值Put(&C,k,e)操作结果:改变复数C的第k元的值为eIsAscending(C)操作结果:如果复数C的两个元素按升序排列,那么返回1,否那么返回0IsDescending(C)操作结果:如果复数C的两个元素按降序排列,那么返回1,否那么返回0Max(C,&e)操作结果:用e返回复数C的两个元素中值较大的一个Min(C,&e)操作结果:用e返回复数C的两个元素中值较小的一个}ADTplexADTRationalNumber{数据对象:D={s,m|s,m为自然数,且m不为0}数据关系:R={}根本操作:InitRationalNumber(&R,s,m)操作结果:构造一个有理数R,其分子和分母分别为s和mDestroyRationalNumber(&R)操作结果:销毁有理数RGet(R,k,&e)操作结果:用e返回有理数R的第k元的值Put(&R,k,e)操作结果:改变有理数R的第k元的值为eIsAscending(R)操作结果:假设有理数R的两个元素按升序排列,那么返回1,否那么返回0IsDescending(R)操作结果:假设有理数R的两个元素按降序排列,那么返回1,否那么返回0Max(R,&e)操作结果:用e返回有理数R的两个元素中值较大的一个Min(R,&e)操作结果:用e返回有理数R的两个元素中值较小的一个}ADTRationalNumber1.5试画出与以下程序段等价的框图。(1)product=1;i=1;while(i<=n){product*=i;i++;}(2)i=0;do{i++;}while((i!=n)&&(a[i]!=x));(3)switch{casexj)j++;elsei++;}(7)x=n;y=0;//n是不小于1的常数while(x>=(y+1)*(y+1)){y++;}(8)x=91;y=100;while(y>0){if(x>100){x-=10;y--;}elsex++;}解:(1)n-1(2)n-1(3)n-1(4)n+(n-1)+(n-2)+...+1=(5)1+(1+2)+(1+2+3)+...+(1+2+3+...+n)===(6)n(7)向下取整(8)11001.9假设n为2的乘幂,并且n>2,试求以下算法的时间复杂度及变量count的值〔以n的函数形式表示〕。intTime(intn){count=0;x=2;while(x题的规模〔即n值的围〕各为多少?哪个算法更适宜?请说明理由。解:n=40n=16那么对于同样的循环次数n,在这个规模下,第二种算法所花费的代价要大得多。故在这个规模下,第一种算法更适宜。1.12设有以下三个函数:,,请判断以下断言正确与否:(1)f(n)是O(g(n))(2)h(n)是O(f(n))(3)g(n)是O(h(n))(4)h(n)是O(n3.5)(5)h(n)是O(nlogn)解:(1)对(2)错(3)错(4)对(5)错1.13试设定假设干n值,比拟两函数和的增长趋势,并确定n在什么围,函数的值大于的值。解:的增长趋势快。但在n较小的时候,的值较大。当n>438时,1.14判断以下各对函数和,当时,哪个函数增长更快?(1),(2),(3),(4),解:(1)g(n)快(2)g(n)快(3)f(n)快(4)f(n)快1.15试用数学归纳法证明:(1)(2)(3)(4)1.16试写一算法,自大至小依次输出顺序读入的三个整数X,Y和Z的值解:intmax3(intx,inty,intz){if(x>y)if(x>z)returnx;elsereturnz;elseif(y>z)returny;elsereturnz;}1.17k阶斐波那契序列的定义为,,…,,;,试编写求k阶斐波那契序列的第m项值的函数算法,k和m均以值调用的形式在函数参数表中出现。解:k>0为阶数,n为数列的第n项intFibonacci(intk,intn){if(k<1)exit(OVERFLOW);int*p,x;p=newint[k+1];if(!p)exit(OVERFLOW);inti,j;for(i=0;i