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中医版分析化学上册习题答案

2018-10-29 8页 doc 24KB 382阅读

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中医版分析化学上册习题答案中医版分析化学上册习题答案 第二章 1、?偶然误差;?系统误差;?系统误差;?过失误差;?系统误 差;?偶然误差;?系统误差;?偶然误差;?系统误差;?偶然误 差;?系统误差;?系统误差;?偶然误差。 2、系统误差中 ?、?、?为恒定误差; ?、?、?、?为比例误差。 3、4、5、6、7略 n ,xix,0.08i,1%,,100%,,100%,0.057%8、(a)35.46;0.02; d 4,35.46nx n ,xix,i0.2,1%,,100%,,100%,0.27%d(b)25.10;0.067; 3,25....
中医版分析化学上册习题答案
中医版分析化学上册习题 第二章 1、?偶然误差;?系统误差;?系统误差;?过失误差;?系统误 差;?偶然误差;?系统误差;?偶然误差;?系统误差;?偶然误 差;?系统误差;?系统误差;?偶然误差。 2、系统误差中 ?、?、?为恒定误差; ?、?、?、?为比例误差。 3、4、5、6、7略 n ,xix,0.08i,1%,,100%,,100%,0.057%8、(a)35.46;0.02; d 4,35.46nx n ,xix,i0.2,1%,,100%,,100%,0.27%d(b)25.10;0.067; 3,25.10nx 9、 (a),:,x,,,35.46,35.53,,0.071E,, (b):,,x,,,25.10,25.06,,0.04故误差(b),(a)1,,E 由上题平均偏差、相对平均偏差结果,偏差(a)< (b) 故;?精密而不准确 (a) ?既不准确也不精密 (b) 10、(a)8.47;0.13;1.6% (b)1.54;0.19;12% 11、(a):疑似离群值8.69,需检验 x,x8.69,8.52相邻离群Q,,,0.46,0.74Q()8.69应保留; 计算0.01,6x,x8.69,8.32maxmin 平均值:8.47;平均偏差:0.094;标准偏差:0.13; x,ts8.47,3.71,0.129,,,,8.47,0.19542平均值的置信区间: n6 (8.27,8.67) (b):疑似离群值1.22,需检验 x,x1.22,1.50相邻离群Q,,,0.61,0.74Q()1.22应保留; 计算0.01,6x,x1.68,1.22maxmin 平均值:1.54;平均偏差:0.14;标准偏差:0.19; x,ts1.54,3.71,0.182,,,1.54,0.2757,平均值的置信区间: n6 (1.26,1.82) -3612、?2.49×10;?3.06×10;?3.90; ?46 ,31.9865,2.86,6.02,1.6740,7.60,1011.701,0.01272(5),,3.412 3.42583.4258 -5 ? 5.0×10 d,0.24;d,0.24(1)(2) 13、 S,0.29S,0.31(1)(2) 标准偏差S能更准确反映数据离散的程度,分辨出精密度的高低。 14、?12.0104;?0.0012;?0.01%;?12.0092-12.0117 第三章重量分析法 2,40.30(1)F,2,MM,,0.36227、 MgOMgPO227222.55?0.5292; ?0.1374; ?1.225; ?0.7643 8、94.54% 、AlAlOHAlO92,2(),323 AlAlO2,23 0.1500,6,10000.1500,6,1000Vml(1),,,20%,21.2NaOH 101.96,05101.96,0.5 ml,22 FW2,26.98,0.1500AlO23Al(2)%,,100%,,100%,78.99% W101.96,0.1005s s10、设应取试样W克: Al(SO),AlO24323 2KAl(SO),AlO4223 WFWFsDAl%,,100%,,,100% DWWAl%s M2MAlSOKAlSOWs()2()24342,,35%,,60%0.15MMAlOAlO2323 解得:W,0.89gs 25973344211、PO,2[(CHN)HPO(,12MoO)H,O] M,1.008PO 25,100%2,M,0.2620[(CHN)H(PO,12MoO),HO]9733442 141.95,1.008,,100%,12.34% 2,M,0.2620 [(CHN)H(PO,12MoO),HO]9733442 M(,2212.8)[(CHN)H(PO,12MoO),HO]9733442 12、解: S?BaSO4 100%32.061005W,MM,0.5,,,0.5,,0.19gssBaSO4 36%233.3936% 绝对误差 13、相对误差,,100% 称取量 ,0.23,Al,AlO相对误差,,100%,,0.1%230.1888 ,0.23,Al,(CHNO)Al相对误差,,100%,,0.01%9631.704第四章 m0.630,10000.0500molC,,,3、? LMV126.07,100.0 m98.00.0500molC,,,? LMV98.07,20.0 m3.000.750molC,,,? LMV40.00,0.0100 m69.00.166molC,,,? LMV208.23,2.00 gg4、1.19,37%,1000mlmmlg12molC,,,HCkLgMV36.46,1Lmol VC1,0.1,1000稀HCLV,,,8.3ml浓HCLC12浓HCL 5、1()1.84,98%,V,1.18,25%,500浓HSO24 V,82ml浓HSO24 (2) CVM,m24HSO稀 ,36,500,98.07,10,1.84,98%,VHSO浓24 V,163mlHSO浓24 6CV,CV、HCl稀稀HCL 0.1000(V,500),0.1332,500加水 V,166ml加水 70.1000,2000,0.0968,1000,12V、浓HCl V,8.6ml 浓HCl --,2,82MnO,5HCO,11H, Mn,10CO,8HO、42422 -2-- HCO,OH, CO,HO24242 n : n,2:5KMnONaOH4 2 CVCV(),()KMnONaOH45 0.1000,22.1020.4420mol C,,,KMnO4L20.005 9、酚酞变色为第一计量点: NaCO,HCl, NaHCO , HO23 32 n : n,1:2HClNaCO 23 0.0987,20.30,105.99NaCO%,,100%,99.70% 23 1000,0.2130第五章 ,,,,(1):HCO、CHO、HO、CHNH、NH、HAc、HS1、2324236534 ,2,2,2,3,,,(2):NO、OH、HPO、CO、CO、HS、PO343244 -,-3、[HO],[OH]-[NO]33 ,--[HO],[OH]-[CN]3 ,,-[HO],[OH]-[NH]34 2-,-[HO],[OH],[CO],[NH]-[HCO]33323 ,- [HO],[OH],[NH]-[HAc]33 3--,-[HO],[PO],[OH],[ HPO]-2[HPO]342434 2--,-[HO],[OH]-[HPO],2[ HPO]-3[HPO]342434 --,-[HO],[OH],[HCO]-2[CO]333 -2-3,,-,,[HO],[OH],[ HPO],2[HPO],3PO32444 、用最简式解题:4 ,141.0,10,,6(1)[OH],K,C,,0.10,7.45,10pOH,5.13b,51.8,10 pH,14,5.13,8.87 ,141.0,10,,6pH,5.13(2)[H],K,C,,0.10,7.45,10a,51.8,10 8(1)KC,1.8,10,0.1,10NaOHNaCOOH、能用直接滴定,计量点生成为一弱碱,4,8a 1.0,10,14[OH],K,C,,0.05,1.67,10pOH,5.78,,61.8,10b,4 pH,14,5.78,8.22剂 ,141.0,10,,6pH,5.13(2)[H],K,C,,0.10,7.45,10a,51.8,10 第七章 2.3180,20.00,10006、(1)C,,0.002183mol/L 169.87,50.00,250.0 0.002183,107.87,3 T,,2.355,10g/ml,AgAgNO/31000 (2) 7、n:n:n,1:1:1 AgNONaClNHSCN34 C,20.00,C,21.00NHSCNAgNO34 0.1173,1000 ,30.00,C,3.20,C NHSCNAgNO3458.49 (1) C,0.07444mol/LAgNO3 ,3(2) T,2.638,10g/mlAgNO,3Cl/ 8、 ,,CVM0.1045,32.29,58.49AgNOAgNONaCl333 %,,100%,,100%,97.46%NaCl,10000.2025,1000WS (0.09500,20.00,0.1100,8.00),58.499、 ,1500,17.90g5.00,1000 10,0.1007,V,74.55,0.1007(30.98,V),119.00,0.3074,1000KClKBrV,14.26mlV,16.72mlKClKBr KCl%,34.83%KBr%,65.175第八章 2,EDTAEDTAC,V,M33Ca5mgml7,Ca,,10/100100 0.00100,0.2502,40.085,,10,10.02mg/100ml100 0.05000,23.90,448.78,,100%,99.30% 0.5400,1000 9、总硬度ppm,VCM,10,0.009434,9.70,100.09,10,91.6ppm 德国度VCM,,0.009434,9.70,56.08,5.13度 CaO 2,Ca,0.009434,8.10,40.08,10,30.63mg/Lmg/L 2, Mg,0.009434,(9.70,8.10),24.305,10,3.67mg/Lmg/L, lgK,25.1lgK,lg,lgK,8() MY,MYYHFe3,10、 lg,25.1,8,17.1lg,17.1()() ,,YHYH pH,1.2min 11、lgK,18.60pH,2lg,13.15NiYYH() , pH,4lg,8.65YH() , ,pH,2时lgK,18.60,13.15,5.09小于8,不能准确滴定MY ,pH,4时lgK,18.60,8.65,9.95大于8,能准确滴定MY 第九章 16、 1E ,0.16,0.059lg,0.16,0.059(1.1,10)Ksp,12 2,,CuCu/ V ,0.16,0.0414,0.708,0.8266 正反应方向进行17、 HAsO2H2eHAsOHO, ,,,,34332 E0.5590.059lg1.0100.033V,10 ,,,,, 可以被碘氧化用来标定碘液19、 n:n,2:1 NaSOAu223 0.00100,V,196.970.06%,,100%V,6.09ml 2000,1.00033,,,, 43AsO,2H,2I,AsO,2I220、 22,, ,I,2SO,2I,SO22346 ,4又:HAsO,NaOH,2e,NaHAsO,HO3422 n:n,2:1 NaSONaOH223 30.00,C,2,30.00,0.1000 NaS2O23 0.1173,1000,30.00,C,3.20,CNHSCNAgNO3458.49 2-2-21、2B?CrO?6SO7232 1001,, 解:0.01667,50,,,0.1098,10.25,0.1458mol,, 2506,, ,2即:样品的物质量0.1458mol,相当于CrO的物质量为 27 0.1458,0.01667,VV,8.75ml2-2-CrOCrO2727 100 按题意每片含盐酸小檗碱为:8.75,0.01360,3,0.099g/片 25023. :,1:5nn KMnO4Fe 0.006023,1000 ,,0.02157/CmolL455.85,5 KMnO 0.1173,1000,30.00,,3.20,CC AgNO34NHSCN58.49 :,2:5 nn2,COKMnO244 0.02157,29.30,134.0,5 %,,100%NaCO224 0.2203,1000,224. ,96.10% n:n,2:5Ca KMnO4 5,0.002000,1.15,40.08Camg/100ml,,100,23.05mg/100ml 10.0025. 2,5.00, 50.00 :,1:6 nn2,苯酚SO23 0.108441.60,30.00,94.11,, 苯酚%,,100%,82.14%25 6000,0.2401,26. 250 1,2(0.77,0.535)7lgK,,7.92K,8.7,10 0.059229. 230,,,CrO,6e,14H,2Cr,7HOE,1.33V272 140.05920.1,3.0E,1.33,lg,1.42V260.030
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