Limiting Reactants #限制反应物#

Limiting Reactants #限制反应物# Limiting Reactants # 1 uzvārds _________________ (Latvian for “surname”) 1. Bob buys 4 packages of hot dogs (each package contains 8 hot dogs) and 5 bags of hot dog buns (each bag contains 6 buns). Calculate the number of properly made hot dog “sandwiches” Bob can produce. (Use proper stoichiometry-like calculations.) What is the limiting reagent? What is in excess and how much is in excess? 4 Packages Hot Dogs x 8 Hot Dogs x 1 hot dog sandwich = 32 hot dog “sandwich” 1 Package 1 hot dog 5 Bags of Buns x 6 buns x 1 hot dog sandwich = 30 hot dog sandwiches 1 Bag 1 Bun Limiting reagent: Buns Excess: 32 hot dogs available – 30 hot dogs used = 2 Hot Dogs in excess 2. A chocolate chip cookie recipe requires 8 eggs and 2 cups of butter to make 4 dozen cookies. George has 2 dozen eggs and 8 cups of butter. What is the limiting reagent? What is in excess and how much is in excess? How many cookies can George make? 24 eggs x 1 Dozen cookies = 3 Dozen Cookies 8 Eggs 8 Cups of Butter x 1 Dozen Cookies = 4 Dozen cookies 2 Cups of Butter Limiting Reagent: Eggs Excess: 24 eggs x 2 cups butter = 6 cups butter used 8 Eggs 8 cups butter available - 6 cups butter used = 2 cups butter in excess Number of cookies made: 24 eggs x 48 cookies made = 144 cookies made 8 Eggs 3. There are 4 Kit Kat bars in a package. Louise likes to put 2 Kit Kat bars with each scoop of ice cream in her nightly sundae. A package of ice cream contains 7.5 scoops. How many sundaes can Louise make if she starts with 42 packages of Kit Kats and 12 packages of ice cream? What is the limiting reagent? What is in excess and how much is in excess? 42 Packages Kit Kat x 4 Kit Kat Bars x 1 Sundae = 84 Sundaes 1 Package 2 Kit Kat Bars 12 Packages Ice Cream x 7.5 Scoops Ice Cream x 1 Sundae = 90 Sundaes 1 Package Ice Cream 1 Scoop of ice cream Sundaes: 84 Limiting Reagent: Kit Kat Excess: 42 Packages Kit Kat x 4 Kit Kat Bars x 1 scoop ice cream = 84 scoops ice cream 1 Package 2 Kit Kat Bars used 12 Packages Ice Cream x 7.5 Scoops Ice Cream = 90 scoops ice cream available 1 Package Ice Cream 90 scoops ice cream available - 84 scoops ice cream used = 6 scoops ice cream excess 4. Mary wants to make calcium sulfate for her home chemistry kit. What mass of calcium sulfate can she make if she starts with 12.6 g of sodium sulfate and 9.532 g of calcium nitrate? What is the limiting reagent? What is in excess and how much is in excess? NaSO + Ca(NO) , 2Na(NO) + Ca SO 2432 34 12.6g NaSO x 1 mole NaSO x 1 mole CaSO x 136.14g CaSO = 12.1g CaSO 2424444 142.04g NaSO 1 mole NaSO 1 mole CaSO 24244 9.532g Ca(NO) x 1 mole Ca(NO)x 1 mole CaSO x 136.14g CaSO= 7.908 g CaSO 32 32 444 164.10g Ca(NO) 1 mole Ca(NO) 1 mole CaSO 32 32 4 mass made: 7.908 g CaSO Limiting Reagent: Ca(NO) 432 9.532g Ca(NO)x 1 mole Ca(NO)x 1 mole NaSO x142.04g NaSO= 8.251 gNaSO 32 32 242424 164.10g Ca(NO) 1 mole Ca(NO) 1 mole NaSO used 32 32 24 12.6g NaSO available - 8.251 g NaSOused = 4.3 g NaSOremaining 2424 24 5. Calculate the volume of nitrogen produced when 57.98 g of nickel (II) nitride reacts with 16.02 L of fluorine to produce nitrogen and nickel (III) fluoride. NiN + 3F , 3NiF + N 32222 57.98g NiNx 1 mole NiN x 1 mole N x 22.4L N = 6.36L N 32 322 22 204.12g NiN1 mole NiN 1 mole N32 322 16.02L Fx 1 mole Fx 1 mole Nx 22.4L N = 5.34 L N *lowest value is product limit 2 2 2 2 2 22.4L F 3 mole F 1 mole N 2 22 Answer 5.34L N 2